Arabian Nights print run
Posted: Fri Jan 21, 2011 5:05 am
So I'm trying to figure out how many of each Arabian Night rare (ie. U2) was printed, and I'm getting confused, so I was hoping some could look at my logic and tell me if it seems, well, logical.
Print run ~5 million cards printed in 11x11 sheets of 121 cards. Each uncommon sheet had 33 U2, 17 U3, and 1 U4 (Oasis). 2*33 + 3*17 + 4*1 = 121, so at least something works out.
5,000,000 / 121 = 41,322.314... <-- not an even number, so it must not be 5 million cards on the dot. Let's assume 41,322 sheets printed. This means there was 4,999,962 cards printed.
Each booster pack had 2 Uncommons and 6 Commons. Therefore 25% of the total cards were uncommons, or 10,330.5 uncommon sheets (still not a round number, this is getting annoying).
#U2 = 2 (cards per sheet) * 10,330 (uncommon sheets) / 33 (different U2's)
#U2 = 626.06
#U3 = 1822.94 (using similar logic as above)
What this is telling me is, that an Arabian Nights Ebony Horse is almost twice as rare as an Alpha rare (known to be ~1100 of each). I just can't believe that this is so, which is why I seek your help.
Also, there has to be a way to do the math such that I only get whole numbers, but I can't figure this out.
Thoughts?
Print run ~5 million cards printed in 11x11 sheets of 121 cards. Each uncommon sheet had 33 U2, 17 U3, and 1 U4 (Oasis). 2*33 + 3*17 + 4*1 = 121, so at least something works out.
5,000,000 / 121 = 41,322.314... <-- not an even number, so it must not be 5 million cards on the dot. Let's assume 41,322 sheets printed. This means there was 4,999,962 cards printed.
Each booster pack had 2 Uncommons and 6 Commons. Therefore 25% of the total cards were uncommons, or 10,330.5 uncommon sheets (still not a round number, this is getting annoying).
#U2 = 2 (cards per sheet) * 10,330 (uncommon sheets) / 33 (different U2's)
#U2 = 626.06
#U3 = 1822.94 (using similar logic as above)
What this is telling me is, that an Arabian Nights Ebony Horse is almost twice as rare as an Alpha rare (known to be ~1100 of each). I just can't believe that this is so, which is why I seek your help.
Also, there has to be a way to do the math such that I only get whole numbers, but I can't figure this out.
Thoughts?